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The natural logarithm of the exponential of x is equal to x. Similarly, the exponential of the natural logarithm of x is equal to x. However, it is important to note that both the natural logarithm and exponentiation operators are not linear. That is to say, ln(a + ≠ ln(a) + ln(. Similarly, exp(a + ≠ exp(a) + exp(b). This common trait of the natural logarithm and exponential function stems from the fact that the exponential function and natural logarithm are inverse operators. If we further or discussion to exponent bases other than euler's number, e, to a base n, we can show that if logₙ(k) = C, nꟲ = k.
Hope this helps.
SOME FUCKING NIGGER FUCKED UP MY POST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
]]>longo is admin's alt, obviously
The natural logarithm of the exponential of x is equal to x. Similarly, the exponential of the natural logarithm of x is equal to x. However, it is important to note that both the natural logarithm and exponentiation operators are not linear. That is to say, ln(a + ≠ ln(a) + ln(. Similarly, exp(a + ≠ exp(a) + exp(b). This common trait of the natural logarithm and exponential function stems from the fact that the exponential function and natural logarithm are inverse operators. If we further or discussion to exponent bases other than euler's number, e, to a base n, we can show that if logₙ(k) = C, nꟲ = k.
Hope this helps.
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